What are the solutions to the equation w^2+4w+4=0 ?

The solutions to the equation w^2+4w+4=0 are w=-2

Find the zeros of w^2+4w+4=0

The zeros of w^2+4w+4=0 are w=-2

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w^{2} + 4 w + 4 = 0

w = - 2

Solution steps

w^{2} + 4 w + 4 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

w_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

w = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

w = - 2

The solution to the quadratic equation is:

w = - 2

X^{2} > 1

- 13 = y - 4

k + 6 > - 20

\frac{1}{2} x^{2} - 1 x - 4 = 0

2 x^{6} + 32 x^{4}

What are the solutions to the equation w^2+4w+4=0 ?
The solutions to the equation w^2+4w+4=0 are w=-2
Find the zeros of w^2+4w+4=0
The zeros of w^2+4w+4=0 are w=-2