What is (5+5i)/(3-4i)+(20)/(4+3i) ?

The solution to (5+5i)/(3-4i)+(20)/(4+3i) is 3-i

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simplify (5+5i)/(3-4i)+(20)/(4+3i)

simplify

\frac{5 + 5 i}{3 - 4 i} + \frac{20}{4 + 3 i}

3 - i

Solution steps

\frac{5 + 5 i}{3 - 4 i} + \frac{20}{4 + 3 i}

\frac{5 + 5 i}{3 - 4 i} = \frac{- 5 + 35 i}{25}

\frac{20}{4 + 3 i} = \frac{80 - 60 i}{25}

= \frac{- 5 + 35 i}{25} + \frac{80 - 60 i}{25}

Join

\frac{- 5 + 35 i}{25} + \frac{80 - 60 i}{25} : \frac{- 25 i + 75}{25}

= \frac{- 25 i + 75}{25}

Factor

- 25 i + 75 : 25 (- i + 3)

= \frac{25 ( - i + 3 )}{25}

Rewrite in standard complex form:

3 - i

= 3 - i

c^{2} + 11 c + 24 = 0

8 x - 4 = \frac{8 x + 5}{2}

\frac{x ^{\frac{1}{2}}}{x ^{\frac{5}{8}}}

4 m + 3 - m = 3 (m + 1)

What is (5+5i)/(3-4i)+(20)/(4+3i) ?
The solution to (5+5i)/(3-4i)+(20)/(4+3i) is 3-i