What are the solutions to the equation 0=-16t^2+96t ?

The solutions to the equation 0=-16t^2+96t are t=0,t=6

Find the zeros of 0=-16t^2+96t

The zeros of 0=-16t^2+96t are t=0,t=6

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0 = - 16 t^{2} + 96 t

t = 0, t = 6

Solution steps

0 = - 16 t^{2} + 96 t

Switch sides

- 16 t^{2} + 96 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 0 = 96

t_{1, 2} = \frac{- 96 \pm 96}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 96}{2 ( - 16 )}, t_{2} = \frac{- 96 - 96}{2 ( - 16 )}

t = \frac{- 96 + 96}{2 ( - 16 )} : 0

t = \frac{- 96 - 96}{2 ( - 16 )} : 6

The solutions to the quadratic equation are:

t = 0, t = 6

7 - 2 x \geq 15

25 \cdot 5

- 3 x^{2} + 4 x = 0

2 x - \frac{1 - 3 x}{10} - \frac{2}{3} = 2 (x - 3) + \frac{1}{5}

3^{- 7}

What are the solutions to the equation 0=-16t^2+96t ?
The solutions to the equation 0=-16t^2+96t are t=0,t=6
Find the zeros of 0=-16t^2+96t
The zeros of 0=-16t^2+96t are t=0,t=6