What are the solutions to the equation 3x^2+5=7x ?

The solutions to the equation 3x^2+5=7x are x= 7/6+i(sqrt(11))/6 ,x= 7/6-i(sqrt(11))/6

Find the zeros of 3x^2+5=7x

The zeros of 3x^2+5=7x are x= 7/6+i(sqrt(11))/6 ,x= 7/6-i(sqrt(11))/6

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3 x^{2} + 5 = 7 x

x = \frac{7}{6} + i \frac{11}{6}, x = \frac{7}{6} - i \frac{11}{6}

Solution steps

3 x^{2} + 5 = 7 x

Move

7 x

to the left side

3 x^{2} + 5 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 7)^{2} - 4 \cdot 3 \cdot 5 : 11 i

x_{1, 2} = \frac{- ( - 7 ) \pm 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 11 i}{2 \cdot 3}

x = \frac{- ( - 7 ) + 11 i}{2 \cdot 3} : \frac{7}{6} + i \frac{11}{6}

x = \frac{- ( - 7 ) - 11 i}{2 \cdot 3} : \frac{7}{6} - i \frac{11}{6}

The solutions to the quadratic equation are:

x = \frac{7}{6} + i \frac{11}{6}, x = \frac{7}{6} - i \frac{11}{6}

\frac{\frac{8}{17}}{\frac{15}{17}}

3 x + 5 = 5 x - 13

\frac{8 ! ( 8 - 4 ) !}{4 !}

\frac{( m ^{2} - 16 n ^{2} )}{\frac{3 m + 12 n}{mn}}

30 m^{2} - 6 m n^{2} + 30 m^{4}

What are the solutions to the equation 3x^2+5=7x ?
The solutions to the equation 3x^2+5=7x are x= 7/6+i(sqrt(11))/6 ,x= 7/6-i(sqrt(11))/6
Find the zeros of 3x^2+5=7x
The zeros of 3x^2+5=7x are x= 7/6+i(sqrt(11))/6 ,x= 7/6-i(sqrt(11))/6