What are the solutions to the equation 5x^2+8x-40=8 ?

The solutions to the equation 5x^2+8x-40=8 are x= 12/5 ,x=-4

Find the zeros of 5x^2+8x-40=8

The zeros of 5x^2+8x-40=8 are x= 12/5 ,x=-4

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5 x^{2} + 8 x - 40 = 8

x = \frac{12}{5}, x = - 4

Decimal Notation

x = 2.4, x = - 4

Solution steps

5 x^{2} + 8 x - 40 = 8

Move

8

to the left side

5 x^{2} + 8 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 ( - 48 )}{2 \cdot 5}

8^{2} - 4 \cdot 5 (- 48) = 32

x_{1, 2} = \frac{- 8 \pm 32}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 8 + 32}{2 \cdot 5}, x_{2} = \frac{- 8 - 32}{2 \cdot 5}

x = \frac{- 8 + 32}{2 \cdot 5} : \frac{12}{5}

x = \frac{- 8 - 32}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = \frac{12}{5}, x = - 4

\frac{16 !}{0 ! ( 16 - 0 ) !}

\frac{64}{3} - \frac{32}{5}

a^{2} - 99 a - 100

\frac{3}{8} \cdot \frac{3}{7}

4 (2 - 3 x) = - 2 x - 27

What are the solutions to the equation 5x^2+8x-40=8 ?
The solutions to the equation 5x^2+8x-40=8 are x= 12/5 ,x=-4
Find the zeros of 5x^2+8x-40=8
The zeros of 5x^2+8x-40=8 are x= 12/5 ,x=-4