What is the answer to solvefor y,x^3-3x^2y=c ?

The answer to solvefor y,x^3-3x^2y=c is y=-(c-x^3)/(3x^2);\quad x\ne 0

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solvefor y,x^3-3x^2y=c

solve for

y, x^{3} - 3 x^{2} y = c

y = - \frac{c - x ^{3}}{3 x ^{2}}; x \neq = 0

Solution steps

x^{3} - 3 x^{2} y = c

Move

x^{3}

to the right side

- 3 x^{2} y = c - x^{3}

Divide both sides by

- 3 x^{2}; x \neq = 0

y = - \frac{c - x ^{3}}{3 x ^{2}}; x \neq = 0

3 ∣ x - 8 ∣ = 12

(1 + \frac{0.02}{4})^{4} - 1

x^{2} + x = 7

\frac{( 2 x + 7 )}{3} - \frac{( 3 x - 6 )}{4} - \frac{( x + 3 )}{2} = \frac{( 4 x + 9 )}{6}

- 2 < 3 x - 2 \leq 7

What is the answer to solvefor y,x^3-3x^2y=c ?
The answer to solvefor y,x^3-3x^2y=c is y=-(c-x^3)/(3x^2);\quad x\ne 0