What are the solutions to the equation 2(x+1)^2=-8 ?

The solutions to the equation 2(x+1)^2=-8 are x=2i-1,x=-2i-1

Find the zeros of 2(x+1)^2=-8

The zeros of 2(x+1)^2=-8 are x=2i-1,x=-2i-1

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2 (x + 1)^{2} = - 8

x = 2 i - 1, x = - 2 i - 1

Solution steps

2 (x + 1)^{2} = - 8

Divide both sides by

2

(x + 1)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 4 : x = 2 i - 1

Solve

x + 1 = - - 4 : x = - 2 i - 1

The solutions to the quadratic equation are:

x = 2 i - 1, x = - 2 i - 1

216 w^{4} - 125 w

5 - 45 x^{5}

1 > \frac{y}{2} - 1

x + 5 = 8

5 x^{2} - 30 x + 6 = 0

What are the solutions to the equation 2(x+1)^2=-8 ?
The solutions to the equation 2(x+1)^2=-8 are x=2i-1,x=-2i-1
Find the zeros of 2(x+1)^2=-8
The zeros of 2(x+1)^2=-8 are x=2i-1,x=-2i-1