What are the solutions to the equation p^2-9p=0 ?

The solutions to the equation p^2-9p=0 are p=9,p=0

Find the zeros of p^2-9p=0

The zeros of p^2-9p=0 are p=9,p=0

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p^{2} - 9 p = 0

p = 9, p = 0

Solution steps

p^{2} - 9 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 0 = 9

p_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 1}, p_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 1}

p = \frac{- ( - 9 ) + 9}{2 \cdot 1} : 9

p = \frac{- ( - 9 ) - 9}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 9, p = 0

x^{3} - 5 x - 2

424

3 y - 4 = 6 - 2 y

\frac{10}{- 1}

\frac{\frac{π}{4}}{3}

What are the solutions to the equation p^2-9p=0 ?
The solutions to the equation p^2-9p=0 are p=9,p=0
Find the zeros of p^2-9p=0
The zeros of p^2-9p=0 are p=9,p=0