What is factor 3^{n+2}+(3^{n+3}-3^{n+1}) ?

The solution to factor 3^{n+2}+(3^{n+3}-3^{n+1}) is 11*3^{n+1}

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factor 3^{n+2}+(3^{n+3}-3^{n+1})

factor

3^{n + 2} + (3^{n + 3} - 3^{n + 1})

11 \cdot 3^{n + 1}

Solution steps

3^{n + 2} + (3^{n + 3} - 3^{n + 1})

Factor

3^{n + 3} - 3^{n + 1} : 3^{n + 1} \cdot 8

= 3^{n + 2} + 3^{n + 1} \cdot 8

Factor out common term

3^{n + 1} : 3^{n + 1} \cdot 11

= 3^{n + 1} \cdot 11

= 11 \cdot 3^{n + 1}

a \cdot a

\frac{6 x}{27} = 43

\frac{8}{3} \cdot 5

3 - 3 x^{2}

\frac{8}{4} - \frac{10}{6} - \frac{3}{9}

What is factor 3^{n+2}+(3^{n+3}-3^{n+1}) ?
The solution to factor 3^{n+2}+(3^{n+3}-3^{n+1}) is 11*3^{n+1}