What is (2x-3)/(x+1)>= 4 ?

The solution to (2x-3)/(x+1)>= 4 is -7/2 <= x<-1

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(2x-3)/(x+1)>= 4

\frac{2 x - 3}{x + 1} \geq 4

- \frac{7}{2} \leq x < - 1

Interval Notation

[- \frac{7}{2}, - 1)

Decimal Notation

- 3.5 \leq x < - 1

Solution steps

\frac{2 x - 3}{x + 1} \geq 4

Rewrite in standard form

\frac{- 2 x - 7}{x + 1} \geq 0

Identify the intervals

- \frac{7}{2} \leq x < - 1

\frac{40 x ^{3} y ^{6}}{- 8 x ^{2} y}

n + 6 \leq - 1

36 b^{2} - 49

15 \geq 5 x

\frac{50}{50 - 3}