What are the solutions to the equation x^2=7x ?

The solutions to the equation x^2=7x are x=7,x=0

Find the zeros of x^2=7x

The zeros of x^2=7x are x=7,x=0

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x^{2} = 7 x

x = 7, x = 0

Solution steps

x^{2} = 7 x

Move

7 x

to the left side

x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

x = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

x = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

(2 x + 3) (4 x + 3) = 0

\frac{3}{b - 8} + \frac{7}{b + 3}

(x^{2})^{\frac{3}{2}}

2^{k} \geq 125

\frac{( 2 x - 1 ) ( x + 4 )}{x - 4} > 0

What are the solutions to the equation x^2=7x ?
The solutions to the equation x^2=7x are x=7,x=0
Find the zeros of x^2=7x
The zeros of x^2=7x are x=7,x=0