What are the solutions to the equation -x^2+8x-6=0 ?

The solutions to the equation -x^2+8x-6=0 are x=4-sqrt(10),x=4+sqrt(10)

Find the zeros of -x^2+8x-6=0

The zeros of -x^2+8x-6=0 are x=4-sqrt(10),x=4+sqrt(10)

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- x^{2} + 8 x - 6 = 0

x = 4 - 10, x = 4 + 10

Decimal Notation

x = 0.83772 \dots, x = 7.16227 \dots

Solution steps

- x^{2} + 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 6) = 210

x_{1, 2} = \frac{- 8 \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 10}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 10}{2 ( - 1 )}

x = \frac{- 8 + 2 10}{2 ( - 1 )} : 4 - 10

x = \frac{- 8 - 2 10}{2 ( - 1 )} : 4 + 10

The solutions to the quadratic equation are:

x = 4 - 10, x = 4 + 10

- 7 + 4 c = 7 c + 6

\frac{210}{( 50 )} + 85

4 \cdot \frac{7}{2}

6 (x - 5) = - 3 x + 42

(- \frac{1}{64})^{\frac{- 2}{3}}

What are the solutions to the equation -x^2+8x-6=0 ?
The solutions to the equation -x^2+8x-6=0 are x=4-sqrt(10),x=4+sqrt(10)
Find the zeros of -x^2+8x-6=0
The zeros of -x^2+8x-6=0 are x=4-sqrt(10),x=4+sqrt(10)