What are the solutions to the equation -(y-3)y=0 ?

The solutions to the equation -(y-3)y=0 are y=3,y=0

Find the zeros of -(y-3)y=0

The zeros of -(y-3)y=0 are y=3,y=0

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- (y - 3) y = 0

y = 3, y = 0

Solution steps

- (y - 3) y = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 3 = 0 or y = 0

Solve

y - 3 = 0 : y = 3

The solutions to the quadratic equation are:

y = 3, y = 0

8 x^{9} + (x - y)^{6}

\frac{3}{4} \cdot \frac{7}{5}

\frac{6 - 7 i}{4 + i}

- 2 ∣ 4 - 2 x ∣ + 9 = 6

(2 a^{2} + 5 a)^{2} - 10 (2 a^{2} + 5 a) - 24

What are the solutions to the equation -(y-3)y=0 ?
The solutions to the equation -(y-3)y=0 are y=3,y=0
Find the zeros of -(y-3)y=0
The zeros of -(y-3)y=0 are y=3,y=0