What is (8x^3y^{-5})/(4x^{-1)y^2} ?

The solution to (8x^3y^{-5})/(4x^{-1)y^2} is (2x^4)/(y^7)

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simplify (8x^3y^{-5})/(4x^{-1)y^2}

simplify

\frac{8 x ^{3} y ^{- 5}}{4 x ^{- 1} y ^{2}}

\frac{2 x ^{4}}{y ^{7}}

Solution steps

\frac{8 x ^{3} y ^{- 5}}{4 x ^{- 1} y ^{2}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 2 x ^{3} y ^{- 5}}{4 x ^{- 1} y ^{2}}

Cancel the common factor:

4

= \frac{2 x ^{3} y ^{- 5}}{x ^{- 1} y ^{2}}

Simplify

\frac{x ^{3}}{x ^{- 1}} : x^{4}

= \frac{2 x ^{4} y ^{- 5}}{y ^{2}}

Simplify

\frac{y ^{- 5}}{y ^{2}} : \frac{1}{y ^{7}}

= \frac{2 x ^{4}}{y ^{7}}

x - 7 < 3 (x + 1)

f = \frac{5 ( - 1 ) + 3}{3 ( - 1 ) - 4}

2 (x + 6)^{2} = 36

125 x^{3} - 64

4 p^{2} - 49

What is (8x^3y^{-5})/(4x^{-1)y^2} ?
The solution to (8x^3y^{-5})/(4x^{-1)y^2} is (2x^4)/(y^7)