What are the solutions to the equation -80=x^2+160x-6400 ?

The solutions to the equation -80=x^2+160x-6400 are x=4(sqrt(795)-20),x=-4(20+sqrt(795))

Find the zeros of -80=x^2+160x-6400

The zeros of -80=x^2+160x-6400 are x=4(sqrt(795)-20),x=-4(20+sqrt(795))

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- 80 = x^{2} + 160 x - 6400

x = 4 (795 - 20), x = - 4 (20 + 795)

Decimal Notation

x = 32.78297 \dots, x = - 192.78297 \dots

Solution steps

- 80 = x^{2} + 160 x - 6400

Switch sides

x^{2} + 160 x - 6400 = - 80

Move

80

to the left side

x^{2} + 160 x - 6320 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 \cdot 1 \cdot ( - 6320 )}{2 \cdot 1}

16 0^{2} - 4 \cdot 1 \cdot (- 6320) = 8795

x_{1, 2} = \frac{- 160 \pm 8 795}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 160 + 8 795}{2 \cdot 1}, x_{2} = \frac{- 160 - 8 795}{2 \cdot 1}

x = \frac{- 160 + 8 795}{2 \cdot 1} : 4 (795 - 20)

x = \frac{- 160 - 8 795}{2 \cdot 1} : - 4 (20 + 795)

The solutions to the quadratic equation are:

x = 4 (795 - 20), x = - 4 (20 + 795)

6 t + 3 (5 t - 4) = 12 (2 t - 5)

0.053 = 1.6365 x + 0.1895

4 - ∣ x - 12 ∣ < 4

x^{4} - 29 x^{2}

- 3 - 48

What are the solutions to the equation -80=x^2+160x-6400 ?
The solutions to the equation -80=x^2+160x-6400 are x=4(sqrt(795)-20),x=-4(20+sqrt(795))
Find the zeros of -80=x^2+160x-6400
The zeros of -80=x^2+160x-6400 are x=4(sqrt(795)-20),x=-4(20+sqrt(795))