What are the solutions to the equation -4x^2+24x-20=0 ?

The solutions to the equation -4x^2+24x-20=0 are x=1,x=5

Find the zeros of -4x^2+24x-20=0

The zeros of -4x^2+24x-20=0 are x=1,x=5

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- 4 x^{2} + 24 x - 20 = 0

x = 1, x = 5

Solution steps

- 4 x^{2} + 24 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 4 ) ( - 20 )}{2 ( - 4 )}

2 4^{2} - 4 (- 4) (- 20) = 16

x_{1, 2} = \frac{- 24 \pm 16}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 24 + 16}{2 ( - 4 )}, x_{2} = \frac{- 24 - 16}{2 ( - 4 )}

x = \frac{- 24 + 16}{2 ( - 4 )} : 1

x = \frac{- 24 - 16}{2 ( - 4 )} : 5

The solutions to the quadratic equation are:

x = 1, x = 5

∣ 3 ∣

9 x - 11 = 5 x + 21

\frac{8}{8} = \frac{n}{56}

\frac{3 x ^{7} y ^{4}}{9 x ^{2} y}

0.8 - 0.002 x = 0

What are the solutions to the equation -4x^2+24x-20=0 ?
The solutions to the equation -4x^2+24x-20=0 are x=1,x=5
Find the zeros of -4x^2+24x-20=0
The zeros of -4x^2+24x-20=0 are x=1,x=5