What are the solutions to the equation -16x^2+3x+32=0 ?

The solutions to the equation -16x^2+3x+32=0 are x=-(-3+11sqrt(17))/(32),x=(3+11sqrt(17))/(32)

Find the zeros of -16x^2+3x+32=0

The zeros of -16x^2+3x+32=0 are x=-(-3+11sqrt(17))/(32),x=(3+11sqrt(17))/(32)

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- 16 x^{2} + 3 x + 32 = 0

x = - \frac{- 3 + 11 17}{32}, x = \frac{3 + 11 17}{32}

Decimal Notation

x = - 1.32356 \dots, x = 1.51106 \dots

Solution steps

- 16 x^{2} + 3 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 16 ) \cdot 32}{2 ( - 16 )}

3^{2} - 4 (- 16) \cdot 32 = 1117

x_{1, 2} = \frac{- 3 \pm 11 17}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 3 + 11 17}{2 ( - 16 )}, x_{2} = \frac{- 3 - 11 17}{2 ( - 16 )}

x = \frac{- 3 + 11 17}{2 ( - 16 )} : - \frac{- 3 + 11 17}{32}

x = \frac{- 3 - 11 17}{2 ( - 16 )} : \frac{3 + 11 17}{32}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 11 17}{32}, x = \frac{3 + 11 17}{32}

\frac{10 + 10 i}{1 + i}

4 y^{2} - 8 y + 3

\frac{\frac{1}{y} - \frac{1}{x}}{x - y}

x^{- \frac{2}{5}}

∣ x + 6 ∣ < 16

What are the solutions to the equation -16x^2+3x+32=0 ?
The solutions to the equation -16x^2+3x+32=0 are x=-(-3+11sqrt(17))/(32),x=(3+11sqrt(17))/(32)
Find the zeros of -16x^2+3x+32=0
The zeros of -16x^2+3x+32=0 are x=-(-3+11sqrt(17))/(32),x=(3+11sqrt(17))/(32)