What are the solutions to the equation 9x^2+6x=-2 ?

The solutions to the equation 9x^2+6x=-2 are x=-1/3+i 1/3 ,x=-1/3-i 1/3

Find the zeros of 9x^2+6x=-2

The zeros of 9x^2+6x=-2 are x=-1/3+i 1/3 ,x=-1/3-i 1/3

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9 x^{2} + 6 x = - 2

x = - \frac{1}{3} + i \frac{1}{3}, x = - \frac{1}{3} - i \frac{1}{3}

Solution steps

9 x^{2} + 6 x = - 2

Move

2

to the left side

9 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 2 : 6 i

x_{1, 2} = \frac{- 6 \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 i}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 i}{2 \cdot 9}

x = \frac{- 6 + 6 i}{2 \cdot 9} : - \frac{1}{3} + i \frac{1}{3}

x = \frac{- 6 - 6 i}{2 \cdot 9} : - \frac{1}{3} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{1}{3}, x = - \frac{1}{3} - i \frac{1}{3}

2 x + 7 \geq - 3

4 - 2 (x + 10) < 12

2 (v + 1) + 4 v = 3 (2 v - 1) + 8

\frac{n ^{2}}{n + 4} - \frac{n + 2}{n ^{2} - 16}

4 n^{9} + 12 n

What are the solutions to the equation 9x^2+6x=-2 ?
The solutions to the equation 9x^2+6x=-2 are x=-1/3+i 1/3 ,x=-1/3-i 1/3
Find the zeros of 9x^2+6x=-2
The zeros of 9x^2+6x=-2 are x=-1/3+i 1/3 ,x=-1/3-i 1/3