What are the solutions to the equation (x+3)(x-3)=16 ?

The solutions to the equation (x+3)(x-3)=16 are x=5,x=-5

Find the zeros of (x+3)(x-3)=16

The zeros of (x+3)(x-3)=16 are x=5,x=-5

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(x + 3) (x - 3) = 16

x = 5, x = - 5

Solution steps

(x + 3) (x - 3) = 16

Expand

(x + 3) (x - 3) : x^{2} - 9

x^{2} - 9 = 16

Move

16

to the left side

x^{2} - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 25) = 10

x_{1, 2} = \frac{- 0 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 10}{2 \cdot 1}, x_{2} = \frac{- 0 - 10}{2 \cdot 1}

x = \frac{- 0 + 10}{2 \cdot 1} : 5

x = \frac{- 0 - 10}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 5, x = - 5

\frac{2 x}{3} + 4 \leq 12 + 2 x

5.0 E 14 = 3.51 x^{2} + 24.4 x + 780

5 x^{2} - 10 x = 0

35 x^{2} - 25 y^{2}

(x - 7) (x + 3) \leq 0

What are the solutions to the equation (x+3)(x-3)=16 ?
The solutions to the equation (x+3)(x-3)=16 are x=5,x=-5
Find the zeros of (x+3)(x-3)=16
The zeros of (x+3)(x-3)=16 are x=5,x=-5