What are the solutions to the equation A^2(pi/(1/2))=1 ?

The solutions to the equation A^2(pi/(1/2))=1 are A=sqrt(1/(2pi)),A=-sqrt(1/(2pi))

Find the zeros of A^2(pi/(1/2))=1

The zeros of A^2(pi/(1/2))=1 are A=sqrt(1/(2pi)),A=-sqrt(1/(2pi))

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A^{2} (\frac{π}{\frac{1}{2}}) = 1

A = \frac{1}{2 π}, A = - \frac{1}{2 π}

Decimal Notation

A = 0.39894 \dots, A = - 0.39894 \dots

Solution steps

A^{2} (\frac{π}{\frac{1}{2}}) = 1

Simplify

\frac{π}{\frac{1}{2}} : 2 π

A^{2} \cdot 2 π = 1

Divide both sides by

2 π

A^{2} = \frac{1}{2 π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

A = \frac{1}{2 π}, A = - \frac{1}{2 π}

\frac{4 x + 1}{3} = \frac{x + 2}{4}

\frac{5}{6} x + \frac{1}{5} \leq \frac{1}{30}

x (x - 2) = - x^{2}

(5 x^{4} y^{3})^{3}

∣ 5 x ∣ > - 4

What are the solutions to the equation A^2(pi/(1/2))=1 ?
The solutions to the equation A^2(pi/(1/2))=1 are A=sqrt(1/(2pi)),A=-sqrt(1/(2pi))
Find the zeros of A^2(pi/(1/2))=1
The zeros of A^2(pi/(1/2))=1 are A=sqrt(1/(2pi)),A=-sqrt(1/(2pi))