What are the solutions to the equation 4z^2+3z-1=0 ?

The solutions to the equation 4z^2+3z-1=0 are z= 1/4 ,z=-1

Find the zeros of 4z^2+3z-1=0

The zeros of 4z^2+3z-1=0 are z= 1/4 ,z=-1

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4 z^{2} + 3 z - 1 = 0

z = \frac{1}{4}, z = - 1

Decimal Notation

z = 0.25, z = - 1

Solution steps

4 z^{2} + 3 z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 1) = 5

z_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- 3 + 5}{2 \cdot 4}, z_{2} = \frac{- 3 - 5}{2 \cdot 4}

z = \frac{- 3 + 5}{2 \cdot 4} : \frac{1}{4}

z = \frac{- 3 - 5}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

z = \frac{1}{4}, z = - 1

2 < x - 2 < 7

y^{\frac{3}{4}} \cdot y^{\frac{1}{3}}

\frac{8}{11} = \frac{x}{3}

x^{2} - 5 x - 66

(\frac{1}{2} t^{2})^{2}

What are the solutions to the equation 4z^2+3z-1=0 ?
The solutions to the equation 4z^2+3z-1=0 are z= 1/4 ,z=-1
Find the zeros of 4z^2+3z-1=0
The zeros of 4z^2+3z-1=0 are z= 1/4 ,z=-1