What are the solutions to the equation 0=x^2+3x-10 ?

The solutions to the equation 0=x^2+3x-10 are x=2,x=-5

Find the zeros of 0=x^2+3x-10

The zeros of 0=x^2+3x-10 are x=2,x=-5

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0 = x^{2} + 3 x - 10

x = 2, x = - 5

Solution steps

0 = x^{2} + 3 x - 10

Switch sides

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

x^{2} = 8 x - 20

∣ 2 x - 3 ∣ = 6

2 + \frac{5}{x} \geq 1

f (x) = e^{- \frac{x}{2}}

- 2 \leq x < 1

What are the solutions to the equation 0=x^2+3x-10 ?
The solutions to the equation 0=x^2+3x-10 are x=2,x=-5
Find the zeros of 0=x^2+3x-10
The zeros of 0=x^2+3x-10 are x=2,x=-5