What are the solutions to the equation x^2+7x-60=0 ?

The solutions to the equation x^2+7x-60=0 are x=5,x=-12

Find the zeros of x^2+7x-60=0

The zeros of x^2+7x-60=0 are x=5,x=-12

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x^{2} + 7 x - 60 = 0

x = 5, x = - 12

Solution steps

x^{2} + 7 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 60) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 1}, x_{2} = \frac{- 7 - 17}{2 \cdot 1}

x = \frac{- 7 + 17}{2 \cdot 1} : 5

x = \frac{- 7 - 17}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 5, x = - 12

\frac{3 ( 632 ) - ( 19 ) ( 102 )}{3 ( 221 ) - ( 19 ) ^{2}}

10 \cdot \frac{4}{35}

12 x y + 14 x + 6 y + 7

x^{2} + 13 x + 30

5 x^{2} - 7 x + 8 = 0

What are the solutions to the equation x^2+7x-60=0 ?
The solutions to the equation x^2+7x-60=0 are x=5,x=-12
Find the zeros of x^2+7x-60=0
The zeros of x^2+7x-60=0 are x=5,x=-12