What are the solutions to the equation m^2-4m+5=0 ?

The solutions to the equation m^2-4m+5=0 are m=2+i,m=2-i

Find the zeros of m^2-4m+5=0

The zeros of m^2-4m+5=0 are m=2+i,m=2-i

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m^{2} - 4 m + 5 = 0

m = 2 + i, m = 2 - i

Solution steps

m^{2} - 4 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

m_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

m = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

m = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

m = 2 + i, m = 2 - i

x^{2} - 14 x + 1 = 0

x (a + b) + 3 (a + b)

- \frac{5}{10}

\frac{1}{x} > - \frac{1}{2}

4 5^{- \frac{3}{2}} \cdot 4 5^{2}

What are the solutions to the equation m^2-4m+5=0 ?
The solutions to the equation m^2-4m+5=0 are m=2+i,m=2-i
Find the zeros of m^2-4m+5=0
The zeros of m^2-4m+5=0 are m=2+i,m=2-i