What are the solutions to the equation 3a=a^2 ?

The solutions to the equation 3a=a^2 are a=3,a=0

Find the zeros of 3a=a^2

The zeros of 3a=a^2 are a=3,a=0

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3 a = a^{2}

a = 3, a = 0

Solution steps

3 a = a^{2}

Switch sides

a^{2} = 3 a

Move

3 a

to the left side

a^{2} - 3 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

a_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

a = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

a = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 3, a = 0

4 c + 7 = 2 c - 1

(- 5 b^{3}) (- 3 b^{6})

- 16 t + 8 t + 80

∣ - 2 x + 3 ∣ \leq 15

71 = - 2 x + 3

What are the solutions to the equation 3a=a^2 ?
The solutions to the equation 3a=a^2 are a=3,a=0
Find the zeros of 3a=a^2
The zeros of 3a=a^2 are a=3,a=0