What is (x^3y^6)^{-2}+(x^2y^4)^{-3} ?

The solution to (x^3y^6)^{-2}+(x^2y^4)^{-3} is 2/(x^6y^{12)}

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simplify (x^3y^6)^{-2}+(x^2y^4)^{-3}

simplify

(x^{3} y^{6})^{- 2} + (x^{2} y^{4})^{- 3}

\frac{2}{x ^{6} y ^{12}}

Solution steps

(x^{3} y^{6})^{- 2} + (x^{2} y^{4})^{- 3}

(x^{3} y^{6})^{- 2} = \frac{1}{x ^{6} y ^{12}}

(x^{2} y^{4})^{- 3} = \frac{1}{x ^{6} y ^{12}}

= \frac{1}{x ^{6} y ^{12}} + \frac{1}{x ^{6} y ^{12}}

Join

\frac{1}{x ^{6} y ^{12}} + \frac{1}{x ^{6} y ^{12}} : \frac{2}{x ^{6} y ^{12}}

= \frac{2}{x ^{6} y ^{12}}

- 4.9 x^{2} + 19.6 x + 58.8 = 0

\frac{x ^{2} - 25}{x - 1} \leq 0

- 6 q - 1 \geq 10 q - 2

6 r^{2} - 10 r - 24

\frac{2 ^{3}}{5}

What is (x^3y^6)^{-2}+(x^2y^4)^{-3} ?
The solution to (x^3y^6)^{-2}+(x^2y^4)^{-3} is 2/(x^6y^{12)}