What are the solutions to the equation y^2-5y=0 ?

The solutions to the equation y^2-5y=0 are y=5,y=0

Find the zeros of y^2-5y=0

The zeros of y^2-5y=0 are y=5,y=0

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y^{2} - 5 y = 0

y = 5, y = 0

Solution steps

y^{2} - 5 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

y_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

y = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

y = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 5, y = 0

4 (y + 2) - y = 2 (y - 1) + 9

2 x^{3} - 3 x^{2} + 1

∣ 2 x + 4 ∣ < 2

\frac{6 \cdot 3}{9}

n^{2} + 3 n = - 2

What are the solutions to the equation y^2-5y=0 ?
The solutions to the equation y^2-5y=0 are y=5,y=0
Find the zeros of y^2-5y=0
The zeros of y^2-5y=0 are y=5,y=0