What are the solutions to the equation 4x^2-4x=-1 ?

The solutions to the equation 4x^2-4x=-1 are x= 1/2

Find the zeros of 4x^2-4x=-1

The zeros of 4x^2-4x=-1 are x= 1/2

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4 x^{2} - 4 x = - 1

x = \frac{1}{2}

Solution steps

4 x^{2} - 4 x = - 1

Move

1

to the left side

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

lo g_{6} (25) = lo g_{6} (5)

- 4 \leq 3 x + 2 < 5

\frac{5 ^{2}}{- 2}

\frac{2 n}{3} + \frac{1}{4} = \frac{3 n - 7}{12}

e^{2 x} \cdot e^{x}

What are the solutions to the equation 4x^2-4x=-1 ?
The solutions to the equation 4x^2-4x=-1 are x= 1/2
Find the zeros of 4x^2-4x=-1
The zeros of 4x^2-4x=-1 are x= 1/2