What are the solutions to the equation x^2-9x+3=0 ?

The solutions to the equation x^2-9x+3=0 are x=(9+sqrt(69))/2 ,x=(9-sqrt(69))/2

Find the zeros of x^2-9x+3=0

The zeros of x^2-9x+3=0 are x=(9+sqrt(69))/2 ,x=(9-sqrt(69))/2

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x^{2} - 9 x + 3 = 0

x = \frac{9 + 69}{2}, x = \frac{9 - 69}{2}

Decimal Notation

x = 8.65331 \dots, x = 0.34668 \dots

Solution steps

x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 3 = 69

x_{1, 2} = \frac{- ( - 9 ) \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 69}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 69}{2 \cdot 1}

x = \frac{- ( - 9 ) + 69}{2 \cdot 1} : \frac{9 + 69}{2}

x = \frac{- ( - 9 ) - 69}{2 \cdot 1} : \frac{9 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 69}{2}, x = \frac{9 - 69}{2}

4 x^{2} - 9 y^{4}

(\frac{1}{8})^{8}

2 y^{2} + 13 y - 24

8 x^{2} + 7 x - 1 = 0

lo g_{\frac{1}{2}} (\frac{x}{1 - x}) \geq - 1

What are the solutions to the equation x^2-9x+3=0 ?
The solutions to the equation x^2-9x+3=0 are x=(9+sqrt(69))/2 ,x=(9-sqrt(69))/2
Find the zeros of x^2-9x+3=0
The zeros of x^2-9x+3=0 are x=(9+sqrt(69))/2 ,x=(9-sqrt(69))/2