What are the solutions to the equation x(x-15)+56=0 ?

The solutions to the equation x(x-15)+56=0 are x=8,x=7

Find the zeros of x(x-15)+56=0

The zeros of x(x-15)+56=0 are x=8,x=7

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x (x - 15) + 56 = 0

x = 8, x = 7

Solution steps

x (x - 15) + 56 = 0

Expand

x (x - 15) + 56 : x^{2} - 15 x + 56

x^{2} - 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

x = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

x = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 8, x = 7

x^{2} - 4 x = 1

4 x \leq 124

\frac{1}{( \frac{3}{2} )}

x (7 - 6 x) = (1 + 3 x) (1 + 2 x)

x - 2 4 - x + 1 \geq 0

What are the solutions to the equation x(x-15)+56=0 ?
The solutions to the equation x(x-15)+56=0 are x=8,x=7
Find the zeros of x(x-15)+56=0
The zeros of x(x-15)+56=0 are x=8,x=7