What is the answer to |x^2-3x|=2 ?

The answer to |x^2-3x|=2 is x=(3-sqrt(17))/2 \lor x=1\lor x=2\lor x=(3+sqrt(17))/2

Solve for x: |x^2-3x|=2

The solution is x=(3-sqrt(17))/2 \lor x=1\lor x=2\lor x=(3+sqrt(17))/2

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x^{2} - 3 x = 2

x = \frac{3 - 17}{2} or x = 1 or x = 2 or x = \frac{3 + 17}{2}

Decimal Notation

x = - 0.56155 \dots, x = 1, x = 2, x = 3.56155 \dots

Solution steps

x^{2} - 3 x = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 3 x = - 2 or x^{2} - 3 x = 2

x^{2} - 3 x = - 2 or x^{2} - 3 x = 2

(x = 1 or x = 2) or (x = \frac{3 - 17}{2} or x = \frac{3 + 17}{2})

x = \frac{3 - 17}{2} or x = 1 or x = 2 or x = \frac{3 + 17}{2}

∣ x - 7 ∣ < - 4

(\frac{3}{2}) 2

100 b^{2} + 9 c^{2} - 60 b c

8 y - 3 (y - 2) > 2 y + 4 (2 y + 4)

40 x^{8} y + 64 x^{4} y

What is the answer to |x^2-3x|=2 ?
The answer to |x^2-3x|=2 is x=(3-sqrt(17))/2 \lor x=1\lor x=2\lor x=(3+sqrt(17))/2
Solve for x: |x^2-3x|=2
The solution is x=(3-sqrt(17))/2 \lor x=1\lor x=2\lor x=(3+sqrt(17))/2