What are the solutions to the equation -4y^2+3y+3=0 ?

The solutions to the equation -4y^2+3y+3=0 are y=-(-3+sqrt(57))/8 ,y=(3+sqrt(57))/8

Find the zeros of -4y^2+3y+3=0

The zeros of -4y^2+3y+3=0 are y=-(-3+sqrt(57))/8 ,y=(3+sqrt(57))/8

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- 4 y^{2} + 3 y + 3 = 0

y = - \frac{- 3 + 57}{8}, y = \frac{3 + 57}{8}

Decimal Notation

y = - 0.56872 \dots, y = 1.31872 \dots

Solution steps

- 4 y^{2} + 3 y + 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 3 = 57

y_{1, 2} = \frac{- 3 \pm 57}{2 ( - 4 )}

Separate the solutions

y_{1} = \frac{- 3 + 57}{2 ( - 4 )}, y_{2} = \frac{- 3 - 57}{2 ( - 4 )}

y = \frac{- 3 + 57}{2 ( - 4 )} : - \frac{- 3 + 57}{8}

y = \frac{- 3 - 57}{2 ( - 4 )} : \frac{3 + 57}{8}

The solutions to the quadratic equation are:

y = - \frac{- 3 + 57}{8}, y = \frac{3 + 57}{8}

2 x - 8 = 0

(2 x - 2) (5 x + 5) = 0

3 x - 110 = 160 + 12 x

9 - x^{2} < 6

15 = c \cdot (c + 2)

What are the solutions to the equation -4y^2+3y+3=0 ?
The solutions to the equation -4y^2+3y+3=0 are y=-(-3+sqrt(57))/8 ,y=(3+sqrt(57))/8
Find the zeros of -4y^2+3y+3=0
The zeros of -4y^2+3y+3=0 are y=-(-3+sqrt(57))/8 ,y=(3+sqrt(57))/8