What are the solutions to the equation 9^2+b^2=14^2 ?

The solutions to the equation 9^2+b^2=14^2 are b=sqrt(115),b=-sqrt(115)

Find the zeros of 9^2+b^2=14^2

The zeros of 9^2+b^2=14^2 are b=sqrt(115),b=-sqrt(115)

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9^{2} + b^{2} = 1 4^{2}

b = 115, b = - 115

Decimal Notation

b = 10.72380 \dots, b = - 10.72380 \dots

Solution steps

9^{2} + b^{2} = 1 4^{2}

Move

9^{2}

to the right side

b^{2} = 115

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 115, b = - 115

\frac{p - 3}{4} - 1 = 2

- 4 + 6

\frac{a ^{2} + 17}{4 a ^{2} - 11 a - 3} - \frac{2}{a - 3}

x^{2} = - 144

∣ v + 5 ∣ - 6 < - 5

What are the solutions to the equation 9^2+b^2=14^2 ?
The solutions to the equation 9^2+b^2=14^2 are b=sqrt(115),b=-sqrt(115)
Find the zeros of 9^2+b^2=14^2
The zeros of 9^2+b^2=14^2 are b=sqrt(115),b=-sqrt(115)