What are the solutions to the equation x^2+2x=-5 ?

The solutions to the equation x^2+2x=-5 are x=-1+2i,x=-1-2i

Find the zeros of x^2+2x=-5

The zeros of x^2+2x=-5 are x=-1+2i,x=-1-2i

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x^{2} + 2 x = - 5

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{2} + 2 x = - 5

Move

5

to the left side

x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

x_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

x = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

x^{- 2} - 3^{- 2}

3 x + 9 - 2 < 7

3 (k - 2) - 4 k (k - 2)

(\frac{1}{3})^{- 3}

7 x (x - 3) = 0

What are the solutions to the equation x^2+2x=-5 ?
The solutions to the equation x^2+2x=-5 are x=-1+2i,x=-1-2i
Find the zeros of x^2+2x=-5
The zeros of x^2+2x=-5 are x=-1+2i,x=-1-2i