What is the answer to (3x-2)/7 =(6x-5)/(13) ?

The answer to (3x-2)/7 =(6x-5)/(13) is x=3

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(3x-2)/7 =(6x-5)/(13)

\frac{3 x - 2}{7} = \frac{6 x - 5}{13}

x = 3

Solution steps

\frac{3 x - 2}{7} = \frac{6 x - 5}{13}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 x - 2) \cdot 13 = 7 (6 x - 5)

Expand

(3 x - 2) \cdot 13 : 39 x - 26

Expand

7 (6 x - 5) : 42 x - 35

39 x - 26 = 42 x - 35

Move

26

to the right side

39 x = 42 x - 9

Move

42 x

to the left side

- 3 x = - 9

Divide both sides by

- 3

x = 3

x + 5 < 20

x^{2} + 3 x - 54 < 0

∣ 5 x - 7 ∣ \leq 3

6 a^{2} + 37 ab + 6 b^{2}

3 x^{2} + 18 x + 24

What is the answer to (3x-2)/7 =(6x-5)/(13) ?
The answer to (3x-2)/7 =(6x-5)/(13) is x=3
Solve for x: (3x-2)/7 =(6x-5)/(13)
The solution is x=3