What are the solutions to the equation 12^2+2^2=x^2 ?

The solutions to the equation 12^2+2^2=x^2 are x=2sqrt(37),x=-2sqrt(37)

Find the zeros of 12^2+2^2=x^2

The zeros of 12^2+2^2=x^2 are x=2sqrt(37),x=-2sqrt(37)

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1 2^{2} + 2^{2} = x^{2}

x = 237, x = - 237

Decimal Notation

x = 12.16552 \dots, x = - 12.16552 \dots

Solution steps

1 2^{2} + 2^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 2^{2}

Simplify

1 2^{2} + 2^{2} : 148

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 148, x = - 148

148 = 237

- 148 = - 237

x = 237, x = - 237

\frac{2}{3 - x} > 1

\frac{( 3 m n ^{2} )}{5 m n ^{2}} (\frac{8 m n ^{3}}{2 mn})^{2}

a - 5 < - 1

- 6 x + 35 = - 6 x + 35

x^{2} y + y + x^{2} + 1

What are the solutions to the equation 12^2+2^2=x^2 ?
The solutions to the equation 12^2+2^2=x^2 are x=2sqrt(37),x=-2sqrt(37)
Find the zeros of 12^2+2^2=x^2
The zeros of 12^2+2^2=x^2 are x=2sqrt(37),x=-2sqrt(37)