What is factor 3^3-3^22x+3*2x^2-2x^3 ?

The solution to factor 3^3-3^22x+3*2x^2-2x^3 is -(2x^3-6x^2+18x-27)

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factor 3^3-3^22x+3*2x^2-2x^3

factor

3^{3} - 3^{2} 2 x + 3 \cdot 2 x^{2} - 2 x^{3}

- (2 x^{3} - 6 x^{2} + 18 x - 27)

Solution steps

3^{3} - 3^{2} \cdot 2 x + 3 \cdot 2 x^{2} - 2 x^{3}

= (- 2 x^{3} + 6 x^{2}) + (- 18 x + 27)

Factor out

- 2 x^{2}

from

- 2 x^{3} + 6 x^{2} : - 2 x^{2} (x - 3)

Factor out

- 9

from

- 18 x + 27 : - 9 (2 x - 3)

= - 2 x^{2} (x - 3) - 9 (2 x - 3)

Factor out

- 1

= - (2 x^{2} (x - 3) + 9 (2 x - 3))

Expand

2 x^{2} (x - 3) + 9 (2 x - 3) : 2 x^{3} - 6 x^{2} + 18 x - 27

= - (2 x^{3} - 6 x^{2} + 18 x - 27)

- 3 (x^{2} - 4) - 10 = 0

2 x + \frac{1}{3} = \frac{2 - 3 x}{4} + 1

3 x^{3} + 5 x^{2} - 3 x - 2

1 + 3 x = - x + 4

w^{2} + 4 w - 5 = 0

What is factor 3^3-3^22x+3*2x^2-2x^3 ?
The solution to factor 3^3-3^22x+3*2x^2-2x^3 is -(2x^3-6x^2+18x-27)