What are the solutions to the equation (x+9)^2=4 ?

The solutions to the equation (x+9)^2=4 are x=-7,x=-11

Find the zeros of (x+9)^2=4

The zeros of (x+9)^2=4 are x=-7,x=-11

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(x + 9)^{2} = 4

x = - 7, x = - 11

Solution steps

(x + 9)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 4 : x = - 7

Solve

x + 9 = - 4 : x = - 11

The solutions to the quadratic equation are:

x = - 7, x = - 11

\frac{7 π}{4} + 2 π

\frac{x - 4}{x - 5} < 0

\frac{- 7}{7}

2 (y - 1) - y (y - 1)

\frac{- \frac{3}{2}}{\frac{1}{2}}

What are the solutions to the equation (x+9)^2=4 ?
The solutions to the equation (x+9)^2=4 are x=-7,x=-11
Find the zeros of (x+9)^2=4
The zeros of (x+9)^2=4 are x=-7,x=-11