3x-5>= 2

Solution

3 x - 5 \geq 2

x \geq \frac{7}{3}

Interval Notation

[\frac{7}{3}, \infty)

Decimal Notation

x \geq 2.33333 \dots

Solution steps

3 x - 5 \geq 2

Move

5

to the right side

3 x \geq 7

Divide both sides by

3

x \geq \frac{7}{3}

\frac{4 x + 6}{2} - 3 = 14

\frac{9 !}{( 9 - 5 ) !}

\frac{5 x}{4} - \frac{3}{17} (x - 20) - (2 x - 1) = \frac{x + 24}{34}

x^{2} = 100

36 - 32