What are the solutions to the equation 3x=-9-4x^2 ?

The solutions to the equation 3x=-9-4x^2 are x=-3/8-i(3sqrt(15))/8 ,x=-3/8+i(3sqrt(15))/8

Find the zeros of 3x=-9-4x^2

The zeros of 3x=-9-4x^2 are x=-3/8-i(3sqrt(15))/8 ,x=-3/8+i(3sqrt(15))/8

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3 x = - 9 - 4 x^{2}

x = - \frac{3}{8} - i \frac{3 15}{8}, x = - \frac{3}{8} + i \frac{3 15}{8}

Solution steps

3 x = - 9 - 4 x^{2}

Switch sides

- 9 - 4 x^{2} = 3 x

Move

3 x

to the left side

- 9 - 4 x^{2} - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} - 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

Simplify

(- 3)^{2} - 4 (- 4) (- 9) : 315 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 15 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 15 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 3 ) - 3 15 i}{2 ( - 4 )}

x = \frac{- ( - 3 ) + 3 15 i}{2 ( - 4 )} : - \frac{3}{8} - i \frac{3 15}{8}

x = \frac{- ( - 3 ) - 3 15 i}{2 ( - 4 )} : - \frac{3}{8} + i \frac{3 15}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} - i \frac{3 15}{8}, x = - \frac{3}{8} + i \frac{3 15}{8}

9 \cdot 36

50 u^{2} v w - 162 v^{3} w

\frac{1}{2} X \leq - 2

8 - (- 6)

x^{3} - 21 x^{2}

What are the solutions to the equation 3x=-9-4x^2 ?
The solutions to the equation 3x=-9-4x^2 are x=-3/8-i(3sqrt(15))/8 ,x=-3/8+i(3sqrt(15))/8
Find the zeros of 3x=-9-4x^2
The zeros of 3x=-9-4x^2 are x=-3/8-i(3sqrt(15))/8 ,x=-3/8+i(3sqrt(15))/8