What are the solutions to the equation 12^2+4^2=c^2 ?

The solutions to the equation 12^2+4^2=c^2 are c=4sqrt(10),c=-4sqrt(10)

Find the zeros of 12^2+4^2=c^2

The zeros of 12^2+4^2=c^2 are c=4sqrt(10),c=-4sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 2^{2} + 4^{2} = c^{2}

c = 410, c = - 410

Decimal Notation

c = 12.64911 \dots, c = - 12.64911 \dots

Solution steps

1 2^{2} + 4^{2} = c^{2}

Switch sides

c^{2} = 1 2^{2} + 4^{2}

Simplify

1 2^{2} + 4^{2} : 160

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 160, c = - 160

160 = 410

- 160 = - 410

c = 410, c = - 410

2 x - 6 = x^{2} - 4 x + 2

- 2 \leq \frac{x - 5}{2} < 3

8 ∣ x - 3 ∣ = - 24

16 n^{2} - 1

e^{x} \cdot e^{3 x}

What are the solutions to the equation 12^2+4^2=c^2 ?
The solutions to the equation 12^2+4^2=c^2 are c=4sqrt(10),c=-4sqrt(10)
Find the zeros of 12^2+4^2=c^2
The zeros of 12^2+4^2=c^2 are c=4sqrt(10),c=-4sqrt(10)