What are the solutions to the equation x^2+11x=7x+21 ?

The solutions to the equation x^2+11x=7x+21 are x=3,x=-7

Find the zeros of x^2+11x=7x+21

The zeros of x^2+11x=7x+21 are x=3,x=-7

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x^{2} + 11 x = 7 x + 21

x = 3, x = - 7

Solution steps

x^{2} + 11 x = 7 x + 21

Move

21

to the left side

x^{2} + 11 x - 21 = 7 x

Move

7 x

to the left side

x^{2} + 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 10}{2 \cdot 1}

x = \frac{- 4 + 10}{2 \cdot 1} : 3

x = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

5 x - 3 (3 x - 3 + 2 x) \geq 2 (3 x - 20 + 4 x)

\frac{100 !}{98 !}

e^{- 0.6}

12 x + 6 = 5 x

6 (\frac{9}{4})

What are the solutions to the equation x^2+11x=7x+21 ?
The solutions to the equation x^2+11x=7x+21 are x=3,x=-7
Find the zeros of x^2+11x=7x+21
The zeros of x^2+11x=7x+21 are x=3,x=-7