What is the answer to solvefor y,sqrt(2-x)yg=x^2-4 ?

The answer to solvefor y,sqrt(2-x)yg=x^2-4 is y=-((x+2)sqrt(2-x))/g ;\quad x\ne 2

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solvefor y,sqrt(2-x)yg=x^2-4

solve for

y, 2 - x y g = x^{2} - 4

y = - \frac{( x + 2 ) 2 - x}{g}; x \neq = 2

Solution steps

2 - x y g = x^{2} - 4

Divide both sides by

2 - x g; x \neq = 2

y = - \frac{( x + 2 ) 2 - x}{g}; x \neq = 2

(2 x - 5)^{2} = 81

4^{x} > 2^{x}

8 x^{2} - x + 2 = 0

7 x^{2} + 7 x + 7

(x^{- 1} + y^{- 1})^{- 2}

What is the answer to solvefor y,sqrt(2-x)yg=x^2-4 ?
The answer to solvefor y,sqrt(2-x)yg=x^2-4 is y=-((x+2)sqrt(2-x))/g ;\quad x\ne 2