What are the solutions to the equation 4^2+6^2=c^2 ?

The solutions to the equation 4^2+6^2=c^2 are c=2sqrt(13),c=-2sqrt(13)

Find the zeros of 4^2+6^2=c^2

The zeros of 4^2+6^2=c^2 are c=2sqrt(13),c=-2sqrt(13)

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4^{2} + 6^{2} = c^{2}

c = 213, c = - 213

Decimal Notation

c = 7.21110 \dots, c = - 7.21110 \dots

Solution steps

4^{2} + 6^{2} = c^{2}

Switch sides

c^{2} = 4^{2} + 6^{2}

Simplify

4^{2} + 6^{2} : 52

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 52, c = - 52

52 = 213

- 52 = - 213

c = 213, c = - 213

\frac{y}{5} - 3 = \frac{y}{2}

x^{2} + (x + 1)^{2} = 85

6 x \leq 3

3 ∣ x + 7 ∣ + 6 \leq 24

\frac{x - 2}{3} - \frac{x - 3}{6} = \frac{3 - x}{2} - 3

What are the solutions to the equation 4^2+6^2=c^2 ?
The solutions to the equation 4^2+6^2=c^2 are c=2sqrt(13),c=-2sqrt(13)
Find the zeros of 4^2+6^2=c^2
The zeros of 4^2+6^2=c^2 are c=2sqrt(13),c=-2sqrt(13)