What are the solutions to the equation 9x^2-6x=2 ?

The solutions to the equation 9x^2-6x=2 are x=(1+sqrt(3))/3 ,x=(1-sqrt(3))/3

Find the zeros of 9x^2-6x=2

The zeros of 9x^2-6x=2 are x=(1+sqrt(3))/3 ,x=(1-sqrt(3))/3

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9 x^{2} - 6 x = 2

x = \frac{1 + 3}{3}, x = \frac{1 - 3}{3}

Decimal Notation

x = 0.91068 \dots, x = - 0.24401 \dots

Solution steps

9 x^{2} - 6 x = 2

Move

2

to the left side

9 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 (- 2) = 63

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 6 3}{2 \cdot 9}

x = \frac{- ( - 6 ) + 6 3}{2 \cdot 9} : \frac{1 + 3}{3}

x = \frac{- ( - 6 ) - 6 3}{2 \cdot 9} : \frac{1 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 3}{3}, x = \frac{1 - 3}{3}

2 x^{2} + 3 x = 6

- \frac{1}{3} - \frac{1}{2} + 3

x ∣ x ∣ \geq 2 x^{2} - 1

2.5 x + 6 = 0.8 x

∣ x + 1 ∣ \leq 3

What are the solutions to the equation 9x^2-6x=2 ?
The solutions to the equation 9x^2-6x=2 are x=(1+sqrt(3))/3 ,x=(1-sqrt(3))/3
Find the zeros of 9x^2-6x=2
The zeros of 9x^2-6x=2 are x=(1+sqrt(3))/3 ,x=(1-sqrt(3))/3