What are the solutions to the equation 5x^2-x+6=0 ?

The solutions to the equation 5x^2-x+6=0 are x= 1/10+i(sqrt(119))/(10),x= 1/10-i(sqrt(119))/(10)

Find the zeros of 5x^2-x+6=0

The zeros of 5x^2-x+6=0 are x= 1/10+i(sqrt(119))/(10),x= 1/10-i(sqrt(119))/(10)

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5 x^{2} - x + 6 = 0

x = \frac{1}{10} + i \frac{119}{10}, x = \frac{1}{10} - i \frac{119}{10}

Solution steps

5 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 6 : 119 i

x_{1, 2} = \frac{- ( - 1 ) \pm 119 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 119 i}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 119 i}{2 \cdot 5}

x = \frac{- ( - 1 ) + 119 i}{2 \cdot 5} : \frac{1}{10} + i \frac{119}{10}

x = \frac{- ( - 1 ) - 119 i}{2 \cdot 5} : \frac{1}{10} - i \frac{119}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{119}{10}, x = \frac{1}{10} - i \frac{119}{10}

4 = \frac{2}{3} (2 x - 9)

\frac{20}{1140} + \frac{24}{1140} + \frac{10}{1140}

5 h + 2 (11 - h) = - 5

24 + f = 16

What are the solutions to the equation 5x^2-x+6=0 ?
The solutions to the equation 5x^2-x+6=0 are x= 1/10+i(sqrt(119))/(10),x= 1/10-i(sqrt(119))/(10)
Find the zeros of 5x^2-x+6=0
The zeros of 5x^2-x+6=0 are x= 1/10+i(sqrt(119))/(10),x= 1/10-i(sqrt(119))/(10)