What are the solutions to the equation 4(x+10)^2+14=26 ?

The solutions to the equation 4(x+10)^2+14=26 are x=sqrt(3)-10,x=-sqrt(3)-10

Find the zeros of 4(x+10)^2+14=26

The zeros of 4(x+10)^2+14=26 are x=sqrt(3)-10,x=-sqrt(3)-10

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4 (x + 10)^{2} + 14 = 26

x = 3 - 10, x = - 3 - 10

Solution steps

4 (x + 10)^{2} + 14 = 26

Move

14

to the right side

4 (x + 10)^{2} = 12

Divide both sides by

4

(x + 10)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 10 = 3 : x = 3 - 10

Solve

x + 10 = - 3 : x = - 3 - 10

The solutions to the quadratic equation are:

x = 3 - 10, x = - 3 - 10

6 p^{2} = - 31 p - 5

0 = 32 - 50 x^{2}

x^{12} - 64

\frac{9 x}{2} - \frac{x}{6} = 2

y (y - 1) - (y - 5)^{2} = 2

What are the solutions to the equation 4(x+10)^2+14=26 ?
The solutions to the equation 4(x+10)^2+14=26 are x=sqrt(3)-10,x=-sqrt(3)-10
Find the zeros of 4(x+10)^2+14=26
The zeros of 4(x+10)^2+14=26 are x=sqrt(3)-10,x=-sqrt(3)-10