What are the solutions to the equation 6^2+12^2=c^2 ?

The solutions to the equation 6^2+12^2=c^2 are c=6sqrt(5),c=-6sqrt(5)

Find the zeros of 6^2+12^2=c^2

The zeros of 6^2+12^2=c^2 are c=6sqrt(5),c=-6sqrt(5)

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6^{2} + 1 2^{2} = c^{2}

c = 65, c = - 65

Decimal Notation

c = 13.41640 \dots, c = - 13.41640 \dots

Solution steps

6^{2} + 1 2^{2} = c^{2}

Switch sides

c^{2} = 6^{2} + 1 2^{2}

Simplify

6^{2} + 1 2^{2} : 180

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 180, c = - 180

180 = 65

- 180 = - 65

c = 65, c = - 65

x^{2} + 5 = - 2 x

\frac{- 56 r ^{3} s ^{5}}{8 r ^{5} s ^{3}}

- \frac{1}{2} + \frac{1}{4}

- x + 4 = 17

\frac{7 ^{5}}{7 ^{3}}

What are the solutions to the equation 6^2+12^2=c^2 ?
The solutions to the equation 6^2+12^2=c^2 are c=6sqrt(5),c=-6sqrt(5)
Find the zeros of 6^2+12^2=c^2
The zeros of 6^2+12^2=c^2 are c=6sqrt(5),c=-6sqrt(5)