What are the solutions to the equation 4x^2-2500=0 ?

The solutions to the equation 4x^2-2500=0 are x=25,x=-25

Find the zeros of 4x^2-2500=0

The zeros of 4x^2-2500=0 are x=25,x=-25

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4 x^{2} - 2500 = 0

x = 25, x = - 25

Solution steps

4 x^{2} - 2500 = 0

Move

2500

to the right side

4 x^{2} = 2500

Divide both sides by

4

x^{2} = 625

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 625, x = - 625

625 = 25

- 625 = - 25

x = 25, x = - 25

8 x + 9 - 12 x = 4 x - 13 + 5 x

42 \cdot 3

\frac{x ^{3} - 5 x ^{2} + 3 x + 9}{x + 1}

x^{2} - 4 x \geq 5

- 37 + m + 28 = - 46

What are the solutions to the equation 4x^2-2500=0 ?
The solutions to the equation 4x^2-2500=0 are x=25,x=-25
Find the zeros of 4x^2-2500=0
The zeros of 4x^2-2500=0 are x=25,x=-25