What is (68)/((1-i)(2-i)(3-i)) ?

The solution to (68)/((1-i)(2-i)(3-i)) is 34/5 i

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simplify (68)/((1-i)(2-i)(3-i))

simplify

\frac{68}{( 1 - i ) ( 2 - i ) ( 3 - i )}

\frac{34}{5} i

Solution steps

\frac{68}{( 1 - i ) ( 2 - i ) ( 3 - i )}

(1 - i) (2 - i) (3 - i) = - 10 i

= \frac{68}{- 10 i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{68 ( - i )}{- 10 i ( - i )}

Simplify

\frac{68 ( - i )}{- 10 i ( - i )} : \frac{- 68 i}{- 10}

= \frac{- 68 i}{- 10}

Cancel

\frac{- 68 i}{- 10} : \frac{34 i}{5}

= \frac{34 i}{5}

Rewrite in standard complex form:

\frac{34}{5} i

= \frac{34}{5} i

\frac{48}{2}

3 (3 y - 8) = 30

∣ x + 1 ∣ ∣ x + 2 ∣ = 3

\frac{x - 7}{x + 5} \geq - 3

2 x^{2} + x \geq 3

What is (68)/((1-i)(2-i)(3-i)) ?
The solution to (68)/((1-i)(2-i)(3-i)) is 34/5 i